2.4e: Exercises - Piecewise Functions, Combinations, Composition (2024)

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A: Concepts

Exercise $\PageIndex{A}$

1) How does one find the domain of the quotient of two functions, $\dfrac{f}{g}$?

2) What is the composition of two functions, $f{\circ}g$?

3) If the order is reversed when composing two functions, can the result ever be the same as the answer in the original order of the composition? If yes, give an example. If no, explain why not.

4) How do you find the domain for the composition of two functions, $f{\circ}g$?

5) How do you graph a piecewise function?

Answers 1-5:

1.Find the numbers that make the function in the denominator $g$ equal to zero, and check for any other domain restrictions on $f$ and $g$, such as an even-indexed root or zeros in the denominator

3. Yes. Sample answer: Let $f(x)=x+1$ and $g(x)=x−1$. Then $f(g(x))=f(x−1)=(x−1)+1=x$ and $g(f(x))=g(x+1)=(x+1)−1=x$. So $f{\circ}g=g{\circ}f$.

5.Graph each formula of the piecewise function over its corresponding domain. Use the same scale for the x-axis and y-axis for each graph. Indicate inclusive endpoints with a solid circle and exclusive endpoints with an open circle. Use an arrow to indicate endpoints of −∞or∞.Combine the graphs to find the graph of the piecewise function

Piecewise Functions

B. Evaluate Piecewise Functions

Exercise $\PageIndex{B}$

Givenfunction $f$, evaluate $f(−3)$, $f(−2)$, $f(−1)$, and $f(0)$.

6. $f(x)= \begin{cases} x+1 & \text{if $x < -2$} \\ -2x-3 & \text{if $x {\geq} -2$} \end{cases}$

7. $f(x)= \begin{cases} 1 & \text{if $x \leq -3$} \\ 0 & \text{if $x > -3$} \end{cases}$

8. $f(x)= \begin{cases} -2x^2+3 & \text{if $x \leq -1$} \\ 5x-7 & \text{if $x > -1$} \end{cases}$

Given function $f$, evaluate $f(−1)$, $f(0)$, $f(2)$, and $f(4)$.

9. $f(x)= \begin{cases} 7x+3 & \text{if $x < 0$} \\ 7x+6 & \text{if $x {\geq} 0$} \end{cases}$

10. $f(x)= \begin{cases} x^2-2 & \text{if $x < 2$} \\ 4+|x-5| & \text{if $x {\geq} 2$} \end{cases}$

11. $f(x)= \begin{cases} 5x & \text{if $x < 0$} \\ 3 & \text{if $0 {\geq} x {\leq} 2$} \\ x^2 & \text{if $x > 3$} \end{cases}$

Write the domain for each piecewise function in interval notation.

12. $f(x)= \begin{cases} x+1 & \text{if $x < -2$} \\ -2x-3 & \text{if $x {\geq} -2$} \end{cases}$

13. $f(x)= \begin{cases} x^2-2 & \text{if $x < 1$} \\ -x^2+2 & \text{if $x > 1$} \end{cases}$

14. $f(x)= \begin{cases} x^2-3 & \text{if $x < 0$} \\ -3x^2 & \text{if $x {\geq} 2$} \end{cases}$

15.Find $f(-5), f(0)$, and $f(3)$ given $f ( x ) = \left\{ \begin{array} { l l } { x ^ { 2 } } & { \text { if } x \leq 0 } \\ { x + 2 } & { \text { if } x > 0 } \end{array} \right. \\[5pt] $

16. Find $f(−3), f(0)$, and $f(2)$ given $f ( x ) = \left\{ \begin{array} { l l } { x ^ { 3 } } & { \text { if } x < 0 } \\ { 2 x - 1 } & { \text { if } x \geq 0 } \end{array} \right. \\[5pt] $

17. Find $g(−1), g(1)$, and $g(4)$ given $g ( x ) = \left\{ \begin{array} { l l } { 5 x - 2 } & { \text { if } x < 1 } \\ { \sqrt { x } } & { \text { if } x \geq 1 } \end{array} \right. \\[5pt] $

18. Find $g(−3), g(−2)$, and $g(−1)$ given $g ( x ) = \left\{ \begin{array} { l } { x ^ { 3 } \text { if } x \leq - 2 } \\ { | x | \text { if } x > - 2 } \end{array} \right.$

19. Find $h(−2), h(0)$, and $h(4)$ given $h ( x ) = \left\{ \begin{array} { l l } { - 5 } & { \text { if } x < 0 } \\ { 2 x - 3 } & { \text { if } 0 \leq x < 2 } \\ { x ^ { 2 } } & { \text { if } x \geq 2 } \end{array} \right. \\[5pt] $

20. Find $h(−5), h(4)$, and $h(25)$ given $h ( x ) = \left\{ \begin{array} { l } { - 3 x \text { if } x \leq 0 } \\ { x ^ { 3 } \text { if } 0 < x \leq 4 } \\ { \sqrt { x } \text { if } x > 4 } \end{array} \right.$

21. Find $f(−2), f(0)$, and $f(3)$ given $f ( x ) = {[{[x-0.5}]}]\\[5pt] $

22. Find $f(−1.2), f(0.4)$, and $f(2.6)$ given $f ( x ) = {[{[2x}]}]+ 1 \\[5pt] $

Answers to Odd Exercises:

7. $f(−3)=1$; $f(−2)=0$; $f(−1)=0$; $f(0)=0$

9. $f(−1)=−4$; $f(0)=6$; $f(2)=20$; $f(4)=34$

11. $f(−1)=−5$; $f(0)=3$; $f(2)=3$; $f(4)=16$

13. domain: $(−\infty,1)\cup(1,\infty)$

15. $f (−5) = 25, f(0) = 0$, and $f(3) = 5$

17. $g(−1) = −7, g(1) = 1$, and $g(4) = 2$

19. $h(−2) = −5, h(0) = −3$, and $h(4) = 16$

21. $f(−2) = −3, f(0) = −1$, and $f(3) = 2$

C:Graph Piecewise Functions

Exercise $\PageIndex{C}$

$ \bigstar $Graph two-part piecewise functions.

$h ( x ) = \left\{ \begin{array} { l l } { x ^ { 2 } + 2 } & { \text { if } x < 0 } \\ { x + 2 } & { \text { if } x \geq 0 } \end{array} \right. \\[2pt] $
$h ( x ) = \left\{ \begin{array} { l l } { x ^ { 2 } - 3 \text { if } x < 0 } \\ { \sqrt { x } - 3 \text { if } x \geq 0 } \end{array} \right. \\[2pt] $
$h ( x ) = \left\{ \begin{array} { l l } { x ^ { 3 } - 1 } & { \text { if } x < 0 } \\ { | x - 3 | - 4 } & { \text { if } x \geq 0 } \end{array} \right. \\[2pt] $
$h ( x ) = \left\{ \begin{array} { c c } { x ^ { 3 } } & { \text { if } x < 0 } \\ { ( x - 1 ) ^ { 2 } - 1 } & { \text { if } x \geq 0 } \end{array} \right. \\[2pt] $
$h ( x ) = \left\{ \begin{array} { l l } { x ^ { 2 } - 1 } & { \text { if } x < 0 } \\ { 2 } & { \text { if } x \geq 0 } \end{array} \right. \\[2pt] $
$h ( x ) = \left\{ \begin{array} { l l } { x + 2 } & { \text { if } x < 0 } \\ { ( x - 2 ) ^ { 2 } } & { \text { if } x \geq 0 } \end{array} \right.$

$g ( x ) = \left\{ \begin{array} { l l } { 2 } & { \text { if } x < 0 } \\ { x } & { \text { if } x \geq 0 } \end{array} \right. \\[2pt] $
$g ( x ) = \left\{ \begin{array} { l l } { x ^ { 2 } } & { \text { if } x < 0 } \\ { 3 } & { \text { if } x \geq 0 } \end{array} \right. \\[2pt] $
$h ( x ) = \left\{ \begin{array} { l l } { x } & { \text { if } x < 0 } \\ { \sqrt { x } } & { \text { if } x \geq 0 } \end{array} \right. \\[2pt] $
$h ( x ) = \left\{ \begin{array} { l } { | x | \text { if } x < 0 } \\ { x ^ { 3 } \text { if } x \geq 0 } \end{array} \right. \\[2pt] $
$f ( x ) = \left\{ \begin{array} { l } { | x | \text { if } x < 2 } \\ { 4 \text { if } x \geq 2 } \end{array} \right.$

$f ( x ) = \left\{ \begin{array} { l l } { x } & { \text { if } x < 1 } \\ { \sqrt { x } } & { \text { if } x \geq 1 } \end{array} \right. \\[2pt] $
$g ( x ) = \left\{ \begin{array} { l l } { x ^ { 2 } \text { if } x \leq - 1 } \\ { x \quad \text { if } x > - 1 } \end{array} \right. \\[2pt] $
$g ( x ) = \left\{ \begin{array} { l } { - 3 \text { if } x \leq - 1 } \\ { x ^ { 3 } \text { if } x > - 1 } \end{array} \right. \\[2pt] $
$h ( x ) = \left\{ \begin{array} { l } { 0 \text { if } x \leq 0 } \\ { \frac { 1 } { x } \text { if } x > 0 } \end{array} \right. \\[2pt] $
$h ( x ) = \left\{ \begin{array} { l } { \frac { 1 } { x } \text { if } x < 0 } \\ { x ^ { 2 } \text { if } x \geq 0 } \end{array} \right.$

Answers to Odd Exercises:

23.

2.4e: Exercises - Piecewise Functions, Combinations, Composition (1)

25.

2.4e: Exercises - Piecewise Functions, Combinations, Composition (2)

27.

2.4e: Exercises - Piecewise Functions, Combinations, Composition (3)

29.

2.4e: Exercises - Piecewise Functions, Combinations, Composition (4)

31.

2.4e: Exercises - Piecewise Functions, Combinations, Composition (5)

33.

2.4e: Exercises - Piecewise Functions, Combinations, Composition (6)

35.

2.4e: Exercises - Piecewise Functions, Combinations, Composition (7)

37.

2.4e: Exercises - Piecewise Functions, Combinations, Composition (8)

$ \bigstar $Graph 3 or more part piecewise functions.

$h ( x ) = \left\{ \begin{array} { l l } { ( x + 10 ) ^ { 2 } - 4 } & { \text { if } x < - 8 } \\ { x + 4 } & { \text { if } - 8 \leq x < - 4 } \\ { \sqrt { x + 4 } } & { \text { if } x \geq - 4 } \end{array} \right. \\[5pt] $
$f ( x ) = \left\{ \begin{array} { l l } { x + 10 } & { \text { if } x \leq - 10 } \\ { | x - 5 | - 15 } & { \text { if } - 10 < x \leq 20 } \\ { 10 } & { \text { if } x > 20 } \end{array} \right. \\[5pt] $
$f ( x ) = \left\{ \begin{array} { l l } { x ^ { 2 } } & { \text { if } x < 0 } \\ { x } & { \text { if } 0 \leq x < 2 } \\ { - 2 } & { \text { if } x \geq 2 } \end{array} \right. \\[5pt] $
$f ( x ) = \left\{ \begin{array} { l l } { x } & { \text { if } x < - 1 } \\ { x ^ { 3 } } & { \text { if } - 1 \leq x < 1 } \\ { 3 } & { \text { if } x \geq 1 } \end{array} \right. \\[5pt] $
$g ( x ) = \left\{ \begin{array} { l l } { 5 } & { \text { if } x < - 2 } \\ { x ^ { 2 } } & { \text { if } - 2 \leq x < 2 } \\ { x } & { \text { if } x \geq 2 } \end{array} \right.$

$g ( x ) = \left\{ \begin{array} { l l } { x } & { \text { if } x < - 3 } \\ { | x | } & { \text { if } - 3 \leq x < 1 } \\ { \sqrt { x } } & { \text { if } x \geq 1 } \end{array} \right. \\[5pt] $
$h ( x ) = \left\{ \begin{array} { l } { \frac { 1 } { x } \text { if } x < 0 } \\ { x ^ { 2 } \text { if } 0 \leq x < 2 } \\ { 4 \text { if } x \geq 2 } \end{array} \right. \\[5pt] $
$h ( x ) = \left\{ \begin{array} { l } { 0 \text { if } x < 0 } \\ { x ^ { 3 } \text { if } 0 < x \leq 2 } \\ { 8 \text { if } x > 2 } \end{array} \right. \\[5pt] $
$f ( x ) ={[{[x+0.5}]}]\\[5pt] $
$f(x) = {[{[x]}]}] +1$
$f(x) = {[{[0.5x}]}] \\[5pt] $
$f(x) = 2 {[{[x}]}] $

Answers to Odd Exercises:

39.

41.

2.4e: Exercises - Piecewise Functions, Combinations, Composition (10)

43.

2.4e: Exercises - Piecewise Functions, Combinations, Composition (11)

45.

2.4e: Exercises - Piecewise Functions, Combinations, Composition (12)

47.

2.4e: Exercises - Piecewise Functions, Combinations, Composition (13)

49.

2.4e: Exercises - Piecewise Functions, Combinations, Composition (14)

D: Graph Piecewise Functions and find their domain

Exercise $\PageIndex{D}$

$ \bigstar $ For each of the following, (a) graph the piecewise function, and (b)state its domain in interval notation.

51. $f(x)= \begin{cases} 2x-1 & \text{if $x < 1$} \\ 1+x & \text{if $x {\geq} 1$} \end{cases}$

52. $f(x)= \begin{cases} x+1 & \text{if $x < -2$} \\ -2x-3 & \text{if $x {\geq} -2$} \end{cases}$

53. $f(x)= \begin{cases} 3 & \text{if $x < 0$} \\ \sqrt{x} & \text{if $x {\geq} 0$} \end{cases}$

54. $f(x)= \begin{cases} x+1 & \text{if $x < 0$} \\ x-1 & \text{if $x > 0$} \end{cases}$

55. $f(x)= \begin{cases} x^2 & \text{if $x < 0$} \\ x+2 & \text{if $x {\geq} 0$} \end{cases}$

56. $f(x)= \begin{cases} x^2 & \text{if $x < 0$} \\ 1-x & \text{if $x > 0$} \end{cases}$

57. $f(x)= \begin{cases} |x| & \text{if $x < 2$} \\ 1 & \text{if $x {\geq} 2$} \end{cases}$

58. $f(x)= \begin{cases} x+1 & \text{if $x < 1$} \\ x^3 & \text{if $x {\geq} 1$} \end{cases}$

Answers to Odd Exercises:

51.

domain: $(−\infty,\infty)$

53.

domain: $(−\infty,\infty)$

55.

domain: $(−\infty,\infty)$

57.

domain: $(−\infty,\infty)$

E: Graph Piecewise Functions and evaluate them

Exercise $\PageIndex{E}$

$ \bigstar $For each of the piecewise-defined functions, (a)sketch the graph, and (b)evaluate at the given values of the independent variable.

59. $f(x)=\begin{cases}x^2-3, & x≤0\\ 4x-3, & x>0\end{cases} \quad \text{Find } f(−4),\; f(0),\; f(2)$

60. $f(x)=\begin{cases}4x+3, & x≤0\\ -x+1, & x>0 \end{cases} \quad \text{Find } f(−3), \;f(0),\;f(2)$

61. $g(x)=\begin{cases}\frac{3}{x−2}, &x≠2\\4, &x=2\end{cases} \quad \text{Find } g(0), \;g(−4),\; g(2)$

62. $h(x)=\begin{cases}x+1, &x≤5\\4, &x>5\end{cases} \quad \text{Find } h(0), \;h(π),\; h(5)$

Answers to Odd Exercises:

59.$ f(−4)=13,\; f(0)=-3,\;f(2)=5$
$\qquad$

2.4e: Exercises - Piecewise Functions, Combinations, Composition (19)

61. a. $g(0)=\frac{−3}{2},\; g(−4)=\frac{−1}{2},\; g(2)=4$
$\qquad$

2.4e: Exercises - Piecewise Functions, Combinations, Composition (20)

F: Construct the equation for a piecewise function given a graph

Exercise $\PageIndex{F}$

$ \bigstar $ (a)Evaluate piecewise function values from agraph. (b) Construct a piecewise function corresponding to the graph.

63. Find $f(-4), f(-2)$, and $f(0)$.	64. Find $f(−3), f(0)$, and $f(1)$.	65. Find $f(0), f(2)$, and $f(4)$.
66. Find $f(−5), f(−2)$, and $f(2)$.	67. Find $f(−3), f(−2)$, and $f(2)$.	68. Find $f(−3), f(0)$, and $f(4)$.
69. Find $f(−2), f(0)$, and $f(2)$.	70. Find $f(−3), f(1)$, and $f(2)$.

Answers to Odd Exercises:: 63. $f(−4) = 1, f(−2) = 1$, and $f(0) = 0 \qquad f(x)=\begin{cases}1, & x≤-2\\ x, & x>-2\end{cases} )$

65. $f(0) = 0, f(2) = 8$, and $f(4) = 0 \qquad\qquad f(x)=\begin{cases}-2, & x≤0\\ \frac{1}{x}, & x>0\end{cases} $

67. $f(−3) = 5, f(−2) = 4$, and $f(2) = 2 \qquad f(x)=\begin{cases}5, & x< -2\\x^2, & -2 \le x < 2\\x, & x \ge 2\end{cases} $

69. $f(−2) = −1, f(0) = 0$, and $f(2) = 1 \qquad f(x)=\begin{cases}-1, & x<0\\ 0, & x=0\\ 1, & x>0\end{cases} $

G: Simplify Combination Functions and Find their Domains

Exercise $\PageIndex{G}$

$ \bigstar $For each pair offunctions $f$ and$g$ given below, find and simplify the combination functions$f+g$, $f−g$, $fg$, and $\dfrac{f}{g}$. State the domain of each combination functionsin interval notation.

71. $f(x)=x^2+2x,$ $g(x)=6−x^2 \\[4pt] $.

72. $f(x)=−3x^2+x,$ $g(x)=5$.

73. $f(x)=2x^2+4x,$ $g(x)=\dfrac{1}{2x}$.

74. $f(x)=\dfrac{1}{x−4},$ $g(x)=\dfrac{1}{6−x}$.

75. $f(x)=3x^2,$ $g(x)=\sqrt{x−5}$.

76. $f(x)=\sqrt{x},$ $g(x)=|x−3|$

Answers to Odd Exercises:

$(f+g)(x)=2x+6$, domain: $(−\infty,\infty)$
$(f−g)(x)=2x^2+2x−6$, domain: $(−\infty,\infty)$
$(fg)(x)=−x^4−2x^3+6x^2+12x$, domain: $(−\infty,\infty)$
$\left(\dfrac{f}{g}\right)(x)=\dfrac{x^2+2x}{6−x^2},$ domain:$ (−\infty,−\sqrt{6})\cup(\sqrt{6},\sqrt{6})\cup(\sqrt{6},\infty)$

$(f+g)(x)=\dfrac{4x^3+8x^2+1}{2x}$, domain: $(−\infty,0)\cup(0,\infty)$
$(f−g)(x)=\dfrac{4x^3+8x^2−1}{2x}$, domain: $(−\infty,0)\cup(0,\infty)$
$(fg)(x)=x+2$, domain: $(−\infty,0)\cup(0,\infty)$
$ \left(\dfrac{f}{g}\right) (x)=4x^3+8x^2$, domain: $(−\infty,0)\cup(0,\infty)$

$(f+g)(x)=3x^2+\sqrt{x−5}$, domain: $\left[5,\infty\right)$
$(f−g)(x)=3x^2−\sqrt{x−5}$, domain: $\left[5,\infty\right)$
$(fg)(x)=3x^2\sqrt{x−5}$, domain: $\left[5,\infty\right)$
$\left(\dfrac{f}{g}\right)(x)=\dfrac{3x^2}{\sqrt{x−5}}$, domain: $(5,\infty)$

Composition

H: Evaluate a Composition fromTables

Exercise $\PageIndex{H}$

$ \bigstar $Use the function values for f and g shown in the table below to evaluate each expression.

$x$	0	1	2	3	4	5	6	7	8	9
$f(x)$	7	6	5	8	4	0	2	1	9	3
$g(x)$	9	5	6	2	1	8	7	3	4	0

78. $f(g(8))$ $\;$79. $f(g(5))$ $\;$80. $g(f(5))$ $\;$81. $g(f(3))$ $\;$82. $f(f(4))$ $\;$83. $f(f(1))$ $\;$84. $g(g(2))$ $\;$85. $g(g(6))$

$ \bigstar $Use the function values for f and g shown in the table below to evaluate each expression.

$x$	-3	-2	-1	0	1	2	3
$f(x)$	11	9	7	5	3	1	-1
$g(x)$	-8	-3	0	1	0	-3	-8

86. $(f{\circ}g)(1)$ $\quad$87. $(f{\circ}g)(2)$ $\quad$88. $(g{\circ}f)(2)$ $\quad$89. $(g{\circ}f)(3)$ $\quad$90. $(g{\circ}g)(1)$ $\quad$91. $(f{\circ}f)(3)$

Answers to Odd Exercises:

79. $9$

81. $4$

83. $2$

85. $3$

87. $11$

89. $0$

91. $ 7 $

I: Evaluate a Composition fromGraphs

Exercise $\PageIndex{I}$

$ \bigstar $Use graphs to evaluate the following compositions.

92. $(f \circg )(3) \\[5pt] $

92.1$(f \circg )(6) \\[5pt] $

93. $(f \circg )(1) \\[5pt] $

94. $(g \circf )(1) \\[5pt] $

95. $(g \circf )(0) $

96. $(f \circf )(5) \\[5pt] $

97. $(f \circf )(4) \\[5pt] $

98. $(g \circg )(2) \\[5pt] $

99. $(g \circg )(0) $

$f$

2.4e: Exercises - Piecewise Functions, Combinations, Composition (29)

$g$

$ \bigstar $Use graphs to evaluate the following compositions.

100. $g(f(1)) \\[5pt] $

101.$g(f(2)) \\[5pt] $

102. $f(g(4)) \\[5pt] $

103. $f(g(1)) \\[5pt] $

104. $f(h(2)) \\[5pt] $

105. $h(f(2)) \\[5pt] $

106. $f(g(h(4))) \\[5pt] $

107. $f(g(f(−2)))$

Answers to Odd Exercises:

93. $2$

95. $5$

97. $4$

99. $0$

101. $2$

103. $1$

105. $4$

107. $4$

J: Evaluate a Composition from Formulas

Exercise $\PageIndex{J}$

$ \bigstar $Use the given pair of functions to find the following values if they exist.

a. $(g\circ f)(0) $

b. $(f\circ g)(-1) $

c. $(f \circ f)(2) $

d. $(g\circ f)(-3) $

e. $(f\circ g)\left(\frac{1}{2}\right) $

f. $(f \circ f)(-2) $

$f(x) = x^2 $, $ g(x) = 2x+1 \\[5pt] $
$f(x) = 4-x $, $ g(x) = 1-x^2 \\[5pt] $
$f(x) = 4-3x $, $ g(x) = |x| \\[5pt] $
$f(x) = |x-1| $, $ g(x) = x^2-5 $

$f(x) = 4x+5 $, $ g(x) = \sqrt{x} \\[5pt] $
$f(x) = \sqrt{3-x} $, $ g(x) = x^2+1 \\[5pt] $
$f(x) = 6-x-x^2 $, $ g(x) = x\sqrt{x+10} \\[5pt] $
$f(x) = \sqrt[3]{x+1} $, $ g(x) = 4x^2-x \\[5pt] $

$f(x) = \dfrac{3}{1-x} $, $ g(x) = \dfrac{4x}{x^2+1} $
$f(x) = \dfrac{x}{x+5} $, $ g(x) = \dfrac{2}{7-x^2} $
$f(x) = \dfrac{2x}{5-x^2} $, $ g(x) = \sqrt{4x+1} $
$f(x) =\sqrt{2x+5} $, $ g(x) = \dfrac{10x}{x^2+1} $

Answers to Odd Exercises

111.$ f(x) = x^2 $, $ g(x) = 2x+1 $:

$(g\circ f)(0) = 1 $
$(f\circ g)(-1) = 1 $
$(f \circ f)(2) = 16 $
$(g\circ f)(-3) = 19 $
$(f\circ g)\left(\frac{1}{2}\right) = 4 $
$(f \circ f)(-2) = 16 $

113. $ f(x) = 4-3x $, $ g(x) = |x| $:

$(g\circ f)(0) = 4 $
$(f\circ g)(-1) = 1 $
$(f \circ f)(2) = 10 $
$(g\circ f)(-3) = 13 $
$(f\circ g)\left(\frac{1}{2}\right) = \frac{5}{2} $
$(f \circ f)(-2) = -26 $

115. $ f(x) = 4x+5 $, $ g(x) = \sqrt{x} $:

$(g\circ f)(0) = \sqrt{5} $
$(f\circ g)(-1) $ is not real
$(f \circ f)(2) = 57 $
$(g\circ f)(-3) $ is not real
$(f\circ g)\left(\frac{1}{2}\right) = 5+2\sqrt{2} $
$(f \circ f)(-2) = -7 $

117.$f(x)=6-x-x^2 $,
$\quad$$ g(x)=x\sqrt{x+10}$

$(g\circ f)(0) = 24 $
$(f\circ g)(-1) = 0 $
$(f \circ f)(2) = 6 $
$(g\circ f)(-3) = 0 $
$(f\circ g)\left(\frac{1}{2}\right) = \frac{27-2\sqrt{42}}{8} $
$(f \circ f)(-2) = -14 $

119. $ f(x) = \frac{3}{1-x} $, $ g(x) = \frac{4x}{x^2+1} $:

$(g\circ f)(0) = \frac{6}{5} $
$(f\circ g)(-1) = 1 $
$(f \circ f)(2) = \frac{3}{4} $
$(g\circ f)(-3) = \frac{48}{25} $
$(f\circ g)\left(\frac{1}{2}\right) = -5 $
$(f \circ f)(-2) $ is undefined

121. $ f(x) = \frac{2x}{5-x^2} $, $ g(x) = \sqrt{4x+1} $:

$(g\circ f)(0) = 1 $
$(f\circ g)(-1) $ is not real
$(f \circ f)(2) = -\frac{8}{11} $
$(g\circ f)(-3) = \sqrt{7} $
$(f\circ g)\left(\frac{1}{2}\right) = \sqrt{3} $
$(f \circ f)(-2) = \frac{8}{11} $

K: Simplify a Composition and Find its Domain

Exercise $\PageIndex{K}$: Find and simplify the Equation for a Composition

$ \bigstar $ Find and simplify (a) $ (f \circ g)(x)$, and (b) $ (g \circ f)(x)$. State the domain for(c) $ (f \circ g)(x)$ andfor(d) $ (g \circ f)(x)$.

$f(x)=x^5$, $g(x)=x+1 \\[5pt] $
$f(x)=|x|$, $g(x)=5x+1 \\[5pt] $
$f(x) = 2x+3 $, $ g(x) = x^2-9 \\[5pt] $
$f(x)=4x+8$, $g(x)=7−x^2 \\[5pt] $
$f(x)=5x+7$, $g(x)=4−2x^2 \\[5pt] $

$f(x)=2x^2+1$, $g(x)=3x+5 \\[5pt] $
$f(x)=2x^2+1$, $g(x)=3x−5 \\[5pt] $
$f(x) = x^2 -x+1 $, $ g(x) = 3x-5 \\[5pt] $
$f(x) = x^2-4 $, $ g(x) = |x| \\[5pt] $

Answers to Odd Exercises: 127. a. $(f \circg )(x) = (x+1)^5$, domain: $(−\infty,\infty) $ $ \qquad $ b. $(g \circf ) (x)= x^5+1 $. domain: $(−\infty,\infty) $
129. a. $(f \circg )(x)=2x^2-15 $, domain: $ (-\infty, \infty) $$ \qquad $ b. $(g \circf ) (x)= 4x^2+12x $, domain: $ (-\infty, \infty) $
131. a. $(f \circg )(x)= 27-10x^2$, domain: $(−\infty,\infty) $$ \;$ b. $(g \circf ) (x)=-50x^2-140x-94 $. domain: $(−\infty,\infty) $
133. a. $(f \circg )(x)= 2(3x−5)^2+1$, domain: $(−\infty,\infty) $$ \qquad $ b. $(g \circf ) (x)= 6x^2−2$. domain: $(−\infty,\infty) $
135. a. $(f \circg )(x)= x^2-4 $,domain: $ (-\infty, \infty) $$ \qquad $ b. $(g \circf ) (x)= |x^2-4| $,domain: $ (-\infty, \infty) $

$ \bigstar $ Find and simplify (a) $ (f \circ g)(x)$, and (b) $ (g \circ f)(x)$. State the domain for(c) $ (f \circ g)(x)$ andfor(d) $ (g \circ f)(x)$.

$f(x) = 3x-5 $, $ g(x) = \sqrt{x} \\[5pt] $
$f(x)=\sqrt{x}+2$, $g(x)=x^2+3 \\[5pt] $
$f(x) = |x+1| $, $ g(x) = \sqrt{x} \\[5pt] $
$f(x) = |x| $, $ g(x) = \sqrt{4-x} \\[5pt] $
$f(x)=x^2+2$,$g(x)=\sqrt{x−2} \\[5pt] $
$f(x)=x^2+1$, $g(x)=\sqrt{x+2} \\[5pt] $

$f(x) = x^2-x-1 $, $ g(x) = \sqrt{x-5} \\[5pt] $
$f(x) = 3-x^2 $, $ g(x) = \sqrt{x+1} \\[5pt] $
$f(x)=\dfrac{1}{\sqrt{x}}$,$g(x)=x^2−4 \\[5pt] $
$f(x)=\dfrac{1}{\sqrt{x}}$,$g(x)=x^2−9 \\[5pt] $
$f(x)=\sqrt{x+4}$, $g(x)=12−x^3 \\[5pt] $
$f(x)=x^3+1$ and $g(x)=\sqrt[3]{x−1}$

Answers to Odd Exercises: 137. a. $(f \circg )(x)= 3 \sqrt{x} -5$, domain: $ [0, \infty) $$ \qquad $ b. $(g \circf ) (x)= \sqrt{3x-5} $. domain: $ [ \frac{5}{3}, \infty ) $
139. a. $(f \circg )(x)= \sqrt{x}+1 $,domain: $ [0,\infty) $$ \qquad $ b. $(g \circf ) (x)= \sqrt{|x+1|} $,domain: $ (-\infty, \infty) $
141. a. $(f \circg )(x)= x$, domain: $ [2,\infty) $$ \qquad $ b. $(g \circf ) (x)= |x| $. domain: $(−\infty,\infty) $
143. a. $(f \circg )(x)= x-6- \sqrt{x-5}$, d: $[5,\infty) $$ \qquad $ b. $(g \circf ) (x)= \sqrt{x^2-x-6} $. d: $(−\infty,-2]\cup[3,\infty) $
145. a. $(f \circg )(x)= \frac{1}{\sqrt{x^2-4}}$, domain: $(−\infty,−2)\cup(2,\infty) $$ \qquad $ b. $(g \circf ) (x)= \frac{1}{x}-4 $. domain: $(0,\infty) $
147. a. $(f \circg )(x)= \sqrt{16-x^3}$, d: $ ( -\infty, 2\sqrt[3]{2} ]$$ \qquad $ b. $(g \circf ) (x)= 12-(x+4) \sqrt{x+4}$. d: $ [-4, \infty) $

$ \bigstar $ Find and simplify (a) $ (f \circ g)(x)$, and (b) $ (g \circ f)(x)$. State the domain for(c) $ (f \circ g)(x)$ andfor(d) $ (g \circ f)(x)$.

$f(x)=\dfrac{1}{x}$,$g(x)=x−3 \\[5pt] $
$f(x)=\frac{1}{x+2}$, $g(x)=4x+3 \\[5pt] $
$f(x) = 3x-1 $, $ g(x) = \dfrac{1}{x+3} \\[5pt] $
$f(x)=\dfrac{1}{x−6}$, $g(x)=\dfrac{7}{x}+6 \\[5pt] $
$f(x)=\dfrac{1}{x−4}$, $g(x)=\dfrac{2}{x}+4 \\[5pt] $
$f(x) = \dfrac{3x}{x-1} $, $ g(x) =\dfrac{x}{x-3} \\[5pt] $

$f(x) = \dfrac{x}{2x+1} $, $ g(x) = \dfrac{2x+1}{x} \\[5pt] $
$f(x)=\dfrac{1−x}{x}$,$g(x)=\dfrac{1}{1+x^2} \\[5pt] $
$f(x)=\dfrac{1}{x}$,$g(x)=\sqrt{x−1} \\[5pt] $
$f(x)=\sqrt{2−4x}$,$g(x)=−\dfrac{3}{x} \\[5pt] $
$f(x)=\sqrt[3]{x}$, $g(x)=\dfrac{x+1}{x^3} \\[5pt] $
$f(x) = \dfrac{2x}{x^2-4} $, $ g(x) =\sqrt{1-x} \\[5pt] $

Answers to Odd Exercises:: 149. a. $(f \circg )(x)= \frac{1}{x-3}$, domain: $(−\infty,3)\cup(3,\infty) $$ \qquad $ b. $(g \circf ) (x)=\frac{1}{x}-3 $. domain: $(−\infty,0)\cup(0,\infty) $
151. a. $(f \circg )(x)= -\frac{x}{x+3} $,d: $ \left(-\infty, -3\right) \cup \left(-3, \infty\right) $$ \qquad $ b. $(g \circf ) (x)= \frac{1}{3x+2} $,d: $ \left(-\infty, -\frac{2}{3}\right) \cup \left(-\frac{2}{3}, \infty\right) $
153. a. $(f \circg )(x)=\dfrac{x}{2} $, domain: $(−\infty,0)\cup(0,\infty) $$ \qquad $ b. $(g \circf ) (x)=2x-4 $. domain: $(−\infty,4)\cup(4,\infty) $
155. a. $(f \circg )(x)= \frac{2x+1}{5x+2} $,d: $ \left(-\infty, -\frac{2}{5}\right) \cup \left(-\frac{2}{5}, 0\right) \cup (0,\infty) $
$ \qquad\;$ b. $(g \circf ) (x)=\frac{4x+1}{x} $,domain: $ \left(-\infty, -\frac{1}{2}\right) \cup \left(-\frac{1}{2}, 0), \cup (0, \infty\right) $
157. a. $(f \circg )(x)= \frac{1}{\sqrt{x-1}}$, domain: $(1,\infty) $$ \qquad $ b. $(g \circf ) (x)= \sqrt{\frac{1}{x}-1}$. domain: $ (0, 1] $
159. a. $(f \circg )(x)= \dfrac{\sqrt[3]{x+1}}{x} $, d: $(−\infty,0)\cup(0,\infty) $$ \qquad $ b. $(g \circf ) (x)= \frac{\sqrt[3]{x}+1}{x} $. d: $(−\infty,0)\cup(0,\infty) $

$ \bigstar $ (a) Findand simplify $(f \circ f)(x) $\and (b) state the domain of the composition.

$f(x) = 2x+3 \\[5pt] $
$f(x) = x^2 -x+1 \\[5pt] $
$f(x) = x^2-4 \\[5pt] $
$f(x) = 3x-5 $

$f(x) = |x+1| \\[5pt] $
$f(x) = 3-x^2 \\[5pt] $
$f(x) = |x| \\[5pt] $
$f(x) = x^2-x-1 $

$f(x) = 3x-1 $
$f(x) = \dfrac{3x}{x-1} $
$f(x) = \dfrac{x}{2x+1} $
$f(x) = \dfrac{2x}{x^2-4} $

$ \bigstar $ Given$ f(x) = -2x $, $ g(x) = \sqrt{x} $ and $ h(x) = |x| $, find and simplify expressions for the following functions and state the domain of each using interval notation.

$(h\circ g \circ f)(x) $
$(h\circ f \circ g)(x) $

$(g\circ f \circ h)(x) $
$(g\circ h \circ f)(x) $

$(f\circ h \circ g)(x) $
$(f\circ g \circ h)(x) $

Answers to Odd Exercises:: 163.$(f \circ f)(x) = 4x+9 $, domain: $ (-\infty, \infty) $
165. $(f \circ f)(x) =x^4-8x^2+12 $,domain: $ (-\infty, \infty) $
167. $(f \circ f)(x) = ||x+1|+1| = |x+1|+1 $,domain: $ (-\infty, \infty) $
169. $(f \circ f)(x) = | |x| | = |x| $,domain: $ (-\infty, \infty) $
171. $(f \circ f)(x) = 9x-4 $,domain: $ (-\infty, \infty) $
173. $(f \circ f)(x) = \frac{x}{4x+1} $,d: $ \left(-\infty, -\frac{1}{2}\right) \cup \left(-\frac{1}{2}, -\frac{1}{4} \right) \cup \left(-\frac{1}{4},\infty\right) $
175. $(h\circ g \circ f)(x)= |\sqrt{-2x}|= \sqrt{-2x} $,domain: $ (-\infty, 0] $
177. $(g\circ f \circ h)(x) = \sqrt{-2|x|} $,domain: $\{0\} $
179. $(f\circ h \circ g)(x) = -2|\sqrt{x}| = -2\sqrt{x} $,domain: $ [0,\infty) $

L: Decomposition

Exercise $\PageIndex{L}$

$ \bigstar $Find functions $f(x)$ and $g(x)$ so the given function can be expressed as $f(g(x))$.

$h(x)=\sqrt { \dfrac{2x−1}{3x+4}}$
$h(x)=(x+2)^2$
$h(x)=(x−5)^3$
$h(x)=\dfrac{3}{x−5}$
$h(x)=\dfrac{4}{(x+2)^2}$
$h(x)=4+\sqrt[3]{x}$
$h(x)=\sqrt[3]{\dfrac{1}{2x−3}}$
$h(x)=\dfrac{1}{(3x^2−4)^{−3}}$

$h(x)=\sqrt[4]{\dfrac{3x−2}{x+5}}$
$h(x)=\left(\dfrac{8+x^3}{8−x^3}\right)^4$
$h(x)=\sqrt{2x+6}$
$h(x)=(5x−1)^3$
$h(x)=\sqrt[3]{x−1}$
$h(x)=|x^2+7|$
$h(x)=\dfrac{1}{(x−2)^3}$
$h(x)=\left(\dfrac{1}{2x−3}\right)^2$
$p(x) = (2x+3)^3 $

$P(x) = \left(x^2-x+1\right)^5 $
$h(x) = \sqrt{2x-1} $
$H(x) = |7-3x| $
$r(x) = \dfrac{2}{5x+1} $
$R(x) = \dfrac{7}{x^2-1} $
$q(x) = \dfrac{|x|+1}{|x|-1} $
$Q(x) = \dfrac{2x^3+1}{x^3-1} $
$v(x) = \dfrac{2x+1}{3-4x} $
$w(x) = \dfrac{x^2}{x^4+1} $

Answers to Odd Exercises:: 185. sample: $f(x)=\sqrt{x}, \quad g(x)=\frac{2x−1}{3x+4}$
187. sample: $f(x)=x^3, \quad g(x)=x−5$
189: sample: $f(x)=\frac{4}{x}, \quad g(x)=(x+2)^2$
191. sample: $f(x)=\sqrt[3]{x}, \quad g(x)=\frac{1}{2x−3}$
193. sample: $f(x)=\sqrt[4]{x}, \quad g(x)=\frac{3x−2}{x+5}$
195. sample: $f(x)=\sqrt{x}, \quad g(x)=2x+6$
197. sample: $f(x)=\sqrt[3]{x}, \quad g(x)=(x−1)$
199. sample: $f(x)=x^3, \quad g(x)=\frac{1}{x−2}$
201. Let $ g(x) = 2x+3 $ and $ f(x) = x^3 $, then $p(x) = (f\circ g)(x) $.
203. Let $ g(x) = 2x-1 $ and $ f(x) = \sqrt{x} $, then $h(x) = (f\circ g)(x) $.
205. Let $ g(x) = 5x+1 $ and $ f(x) = \frac{2}{x} $, then $r(x) =(f\circ g)(x) $.
207. Let $ g(x) = |x| $ and $ f(x) = \frac{x+1}{x-1} $, then $q(x) =(f\circ g)(x) $.
209. Let $ g(x) =2x $ and $ f(x) = \frac{x+1}{3-2x} $, then $v(x) =(f\circ g)(x) $.

63. Find \(f(-4), f(-2)\), and \(f(0)\).	64. Find \(f(−3), f(0)\), and \(f(1)\).	65. Find \(f(0), f(2)\), and \(f(4)\).
66. Find \(f(−5), f(−2)\), and \(f(2)\).	67. Find \(f(−3), f(−2)\), and \(f(2)\).	68. Find \(f(−3), f(0)\), and \(f(4)\).
69. Find \(f(−2), f(0)\), and \(f(2)\).	70. Find \(f(−3), f(1)\), and \(f(2)\).

\(x\)	0	1	2	3	4	5	6	7	8	9
\(f(x)\)	7	6	5	8	4	0	2	1	9	3
\(g(x)\)	9	5	6	2	1	8	7	3	4	0

\(x\)	-3	-2	-1	0	1	2	3
\(f(x)\)	11	9	7	5	3	1	-1
\(g(x)\)	-8	-3	0	1	0	-3	-8